Let $\alpha$ and $\beta$ be elements of $\mathcal{S}_n$. Prove that
${\alpha}^{-1}{\beta}^{-1}\alpha \beta$ is an even permutation.
Solution
The sign function ($1$ for an even permutation and $-1$ for an odd permutation) is a homomorpism from the symmetric group to a group with two elements. That two-element group is abelian (commutative), so the product of a bunch of elements and their inverses in it, in any order, is the identity. Pull back, and the product of the original elements and their inverses was an even permutation.
Solution
The sign function ($1$ for an even permutation and $-1$ for an odd permutation) is a homomorpism from the symmetric group to a group with two elements. That two-element group is abelian (commutative), so the product of a bunch of elements and their inverses in it, in any order, is the identity. Pull back, and the product of the original elements and their inverses was an even permutation.
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