Give an example of a continuous function $f:[1, +\infty) \rightarrow \mathbb{R}$ such that $f(x)>0$ forall $x \in [1, +\infty)$ and $\bigintsss_{1}^{\infty} f(x) \, {\rm d}x$ converges while $\bigintsss_{1}^{\infty} f^2(x) \, {\rm d}x$ diverges.
Solution
Define $f$ by
$$f(x) = e^{-x} + \sum_{n=2}^{\infty} \max\{0, n - n^4|x - n|\}$$
Hence
$$\int_{1}^{\infty} f(x) \, \mathrm{d}x = \int_{1}^{\infty} \mathrm{e}^{-x} \, \mathrm{d}x + \sum_{n=2}^{\infty} \frac{1}{n^2}$$
which clearly converges , but on the other hand
$$ \int_{1}^{\infty} f^2(x) \, \mathrm{d}x \geq \sum_{n=2}^{\infty} \int_1^{\infty} \max\{0, (n - n^4|x - n|)^2 \} \, \mathrm{d}x = \sum_{n=2}^{\infty} \frac{2}{3n} = \infty$$
The basic idea is to construct a train of picks. Picks are constructed to satisfy the following heuristics: Each pick at $x = n$ is of height $\sim n$ and width $\sim n^{-3}$, thus the area is of order $\sim n^{-2}$, when squared, however, its height gets squared and the area becomes of order $\sim n^{-1}$.
Solution
Define $f$ by
$$f(x) = e^{-x} + \sum_{n=2}^{\infty} \max\{0, n - n^4|x - n|\}$$
Hence
$$\int_{1}^{\infty} f(x) \, \mathrm{d}x = \int_{1}^{\infty} \mathrm{e}^{-x} \, \mathrm{d}x + \sum_{n=2}^{\infty} \frac{1}{n^2}$$
which clearly converges , but on the other hand
$$ \int_{1}^{\infty} f^2(x) \, \mathrm{d}x \geq \sum_{n=2}^{\infty} \int_1^{\infty} \max\{0, (n - n^4|x - n|)^2 \} \, \mathrm{d}x = \sum_{n=2}^{\infty} \frac{2}{3n} = \infty$$
The basic idea is to construct a train of picks. Picks are constructed to satisfy the following heuristics: Each pick at $x = n$ is of height $\sim n$ and width $\sim n^{-3}$, thus the area is of order $\sim n^{-2}$, when squared, however, its height gets squared and the area becomes of order $\sim n^{-1}$.
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